Point 4.- Case of Roots
An implication that zero multiplied by zero does not result in zero is that zero does not have any numbers as a square root for there is no number with which, multiplied by another number equal to it, the multiplication results in zero. Zero does not have any numbers as a square root, as a fourth root, as a sixth root, etc, but does have a number as a cube root, as a fifth root, as a seventh root, etc for an odd quantity of factors zero does result in zero whereas an even quantity of factors zero results in every number except zero.
0x0x0x0 =
= The set of all numbers except zero.0x0x0 =
= 00x0x0x0 = (0x0)x(0x0) = the set of all numbers except zero multiplied by the set of all numbers except zero = the set of all numbers except zero
OR
0x0x0x0 = (0x0x0)x0 = 0x0 = the set of all numbers except zero.
0x0x0 = (0x0)x0 = (the set of all numbers except zero)x0 = 0
Point 5.- Another important exception
=
(for b or c different from zero).
=
but
is different from
.Point 6.- Reasoning
=
= 0
=
= 0x0 = the set of all numbers except zero.1/3 = 2/6
2/3 = 4/6 = 1/3+2/6
so a)
=
=
=
. As we've already seen, zero does not have any numbers as a square root, as a fourth root, as a sixth root, etc.
=
= empty set.
=
=
=
= empty set multiplied by empty set. (
symbol of empty set) So
results in
, which is equal to zero.
=
. So
= 0.b)
=
=
=
=
=
=
=
.So
=
=
= 0x0 = the set of all numbers except zero.So
= the set of all numbers different from zero.c)
=
=
=
=
.
=
=
=
So
=
.THEREFORE empty set multiplied by empty set results in empty set as well as it results in every number, INCLUDING zero.
ASTONISHED?? I think you shouldn't. This reasoning is only a theory for part b is based on the assumption that the associative law is applicable to factors which are empty set BUT there is a fact that seems to support this part (note that parts a and c do not need any additional support). In conventional Mathematics itself, there are the so called Imaginary Numbers. The product of two real numbers of the same sign is a positive number (+2 x +3 = +6, -2 x -3 = +6) but the product of two imaginary numbers of the same sign is a negative one (+2i x +3i = -6). These so called imaginary numbers are not real numbers (so they are not numbers at all). Therefore, couldn't they be some particular manifestations of empty set?
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